Integrand size = 30, antiderivative size = 164 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=-\frac {\sqrt {b-\sqrt {b^2-4 a c}} \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b-\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} \sqrt {b^2-4 a c} e}+\frac {\sqrt {b+\sqrt {b^2-4 a c}} \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} \sqrt {b^2-4 a c} e} \]
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Time = 0.11 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {1156, 1144, 211} \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\frac {\sqrt {\sqrt {b^2-4 a c}+b} \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {\sqrt {b^2-4 a c}+b}}\right )}{\sqrt {2} \sqrt {c} e \sqrt {b^2-4 a c}}-\frac {\sqrt {b-\sqrt {b^2-4 a c}} \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b-\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} e \sqrt {b^2-4 a c}} \]
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Rule 211
Rule 1144
Rule 1156
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^2}{a+b x^2+c x^4} \, dx,x,d+e x\right )}{e} \\ & = \frac {\left (1-\frac {b}{\sqrt {b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\frac {b}{2}-\frac {1}{2} \sqrt {b^2-4 a c}+c x^2} \, dx,x,d+e x\right )}{2 e}+\frac {\left (1+\frac {b}{\sqrt {b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\frac {b}{2}+\frac {1}{2} \sqrt {b^2-4 a c}+c x^2} \, dx,x,d+e x\right )}{2 e} \\ & = -\frac {\sqrt {b-\sqrt {b^2-4 a c}} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b-\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} \sqrt {b^2-4 a c} e}+\frac {\sqrt {b+\sqrt {b^2-4 a c}} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} \sqrt {b^2-4 a c} e} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.07 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\frac {\left (-b+\sqrt {b^2-4 a c}\right ) \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b-\sqrt {b^2-4 a c}}}\right )+\sqrt {b-\sqrt {b^2-4 a c}} \sqrt {b+\sqrt {b^2-4 a c}} \arctan \left (\frac {\sqrt {2} \sqrt {c} (d+e x)}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )}{\sqrt {2} \sqrt {c} \sqrt {b^2-4 a c} \sqrt {b-\sqrt {b^2-4 a c}} e} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.59 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.85
method | result | size |
default | \(\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (c \,e^{4} \textit {\_Z}^{4}+4 c d \,e^{3} \textit {\_Z}^{3}+\left (6 c \,d^{2} e^{2}+b \,e^{2}\right ) \textit {\_Z}^{2}+\left (4 d^{3} e c +2 b d e \right ) \textit {\_Z} +d^{4} c +b \,d^{2}+a \right )}{\sum }\frac {\left (\textit {\_R}^{2} e^{2}+2 \textit {\_R} d e +d^{2}\right ) \ln \left (x -\textit {\_R} \right )}{2 e^{3} c \,\textit {\_R}^{3}+6 c d \,e^{2} \textit {\_R}^{2}+6 c \,d^{2} e \textit {\_R} +2 d^{3} c +b e \textit {\_R} +b d}}{2 e}\) | \(140\) |
risch | \(\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (c \,e^{4} \textit {\_Z}^{4}+4 c d \,e^{3} \textit {\_Z}^{3}+\left (6 c \,d^{2} e^{2}+b \,e^{2}\right ) \textit {\_Z}^{2}+\left (4 d^{3} e c +2 b d e \right ) \textit {\_Z} +d^{4} c +b \,d^{2}+a \right )}{\sum }\frac {\left (\textit {\_R}^{2} e^{2}+2 \textit {\_R} d e +d^{2}\right ) \ln \left (x -\textit {\_R} \right )}{2 e^{3} c \,\textit {\_R}^{3}+6 c d \,e^{2} \textit {\_R}^{2}+6 c \,d^{2} e \textit {\_R} +2 d^{3} c +b e \textit {\_R} +b d}}{2 e}\) | \(140\) |
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Leaf count of result is larger than twice the leaf count of optimal. 703 vs. \(2 (129) = 258\).
Time = 0.25 (sec) , antiderivative size = 703, normalized size of antiderivative = 4.29 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\frac {1}{2} \, \sqrt {\frac {1}{2}} \sqrt {-\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \log \left (\sqrt {\frac {1}{2}} {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} \sqrt {-\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + e x + d\right ) - \frac {1}{2} \, \sqrt {\frac {1}{2}} \sqrt {-\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \log \left (-\sqrt {\frac {1}{2}} {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} \sqrt {-\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + e x + d\right ) - \frac {1}{2} \, \sqrt {\frac {1}{2}} \sqrt {\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} - b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \log \left (\sqrt {\frac {1}{2}} {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} \sqrt {\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} - b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + e x + d\right ) + \frac {1}{2} \, \sqrt {\frac {1}{2}} \sqrt {\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} - b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \log \left (-\sqrt {\frac {1}{2}} {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} \sqrt {\frac {{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} - b}{{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}}} \sqrt {\frac {1}{{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} e^{4}}} + e x + d\right ) \]
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Time = 0.73 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.63 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\operatorname {RootSum} {\left (t^{4} \cdot \left (256 a^{2} c^{3} e^{4} - 128 a b^{2} c^{2} e^{4} + 16 b^{4} c e^{4}\right ) + t^{2} \left (- 16 a b c e^{2} + 4 b^{3} e^{2}\right ) + a, \left ( t \mapsto t \log {\left (x + \frac {64 t^{3} a c^{2} e^{3} - 16 t^{3} b^{2} c e^{3} - 2 t b e + d}{e} \right )} \right )\right )} \]
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\[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\int { \frac {{\left (e x + d\right )}^{2}}{{\left (e x + d\right )}^{4} c + {\left (e x + d\right )}^{2} b + a} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 1403 vs. \(2 (129) = 258\).
Time = 0.29 (sec) , antiderivative size = 1403, normalized size of antiderivative = 8.55 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=\text {Too large to display} \]
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Time = 0.21 (sec) , antiderivative size = 590, normalized size of antiderivative = 3.60 \[ \int \frac {(d+e x)^2}{a+b (d+e x)^2+c (d+e x)^4} \, dx=-2\,\mathrm {atanh}\left (\frac {\sqrt {-\frac {b^3+\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-4\,a\,b\,c}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}}\,\left (x\,\left (4\,a\,c^2\,e^{12}-2\,b^2\,c\,e^{12}\right )+\frac {\left (x\,\left (8\,b^3\,c^2\,e^{14}-32\,a\,b\,c^3\,e^{14}\right )+8\,b^3\,c^2\,d\,e^{13}-32\,a\,b\,c^3\,d\,e^{13}\right )\,\left (b^3+\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-4\,a\,b\,c\right )}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}+4\,a\,c^2\,d\,e^{11}-2\,b^2\,c\,d\,e^{11}\right )}{a\,c\,e^{10}}\right )\,\sqrt {-\frac {b^3+\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-4\,a\,b\,c}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}}-2\,\mathrm {atanh}\left (\frac {\sqrt {\frac {\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-b^3+4\,a\,b\,c}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}}\,\left (x\,\left (4\,a\,c^2\,e^{12}-2\,b^2\,c\,e^{12}\right )-\frac {\left (x\,\left (8\,b^3\,c^2\,e^{14}-32\,a\,b\,c^3\,e^{14}\right )+8\,b^3\,c^2\,d\,e^{13}-32\,a\,b\,c^3\,d\,e^{13}\right )\,\left (\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-b^3+4\,a\,b\,c\right )}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}+4\,a\,c^2\,d\,e^{11}-2\,b^2\,c\,d\,e^{11}\right )}{a\,c\,e^{10}}\right )\,\sqrt {\frac {\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-b^3+4\,a\,b\,c}{8\,\left (16\,a^2\,c^3\,e^2-8\,a\,b^2\,c^2\,e^2+b^4\,c\,e^2\right )}} \]
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